Hello all,
I might be missing something but I do not understand how this circuit can operate...
The forward voltage drop of most LED's is about 2v +-... your Battery is only 1.5 volts...
It appears to me the LED will not turn on...
If that is correct, you will need two batteries to have a chance.
Hope this helps.
You are missing the voltage-doubling action of charging the large capacitor to the battery voltage, then switching it in-series with the LED to double the applied voltage to the LED, and letting the capacitor discharge through the LED.
Propabaly time to ask "what is he trying to do"... too many variables. Duration/brightness(and color)
Bottom Line... power density is power density... (Only so many electrons available in any given battery power source.)
Then apply the math before soldering components. At least you have a rough idea of the outcome...
Floyd
I made some LED flashlights with different coloured LEDs and powered from a 9V battery. The battery lasts for a long time because my circuit blinks the LED very brightly but for short duration pulses 5 times then a pause before blinking again. The bursts of 5 pulses occur once per second. The LED is turned off for most of the time but I can see fine at night on walks and at the barbeque.