In the previous circuit, pin 7 of a 555 connects to a transistor inside the chip that only takes pin 7 to ground. It does not source any current.
Secondly, how are you discharging the capacitors in the circuit?
What is the circuit supposed to do?
In the last circuit posted, could you make it any more complex?
How about adding a microcontroller and switch-mode power supply and a detecting circuit to detect when a LED fails.
You wonder why the Chinese and Taiwanese have taken over the electronics market.