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With no amplification, the shunt would be 10 ohms, and the voltage drop across it at 1A would be (surprise!) 10V. The Dissipation would be 10W. At 2A, the dissipation would be 40W. It would be cheaper and easier to buy a multimeter. If this is for a power supply, it could be done with some amplification.I have an analog voltmeter and I can read current this too.
I wonder if you can add a switch with a shunt to a voltmeter to also read current. The problem I have is to make the scale being: 10v = 1A, 2A = 20v, 1A = 30R . Any circuits ideas?
Sorry my english
Thanks!
Frankli