And or not etc in Oshonsoft

camerart said:

Hi,
I have lines like;
blah (apple OR banana OR orange OR peach)
and similarly:
blah (apple AND banana AND orange AND peach)

When using the suggestions does it matter if they are 'done' in different orders? In other words, if I first (apple OR banana) then (orange OR peach) then (res1 OR res2) or 'say' OR each fruit as I go along? Similarly for AND.
C.

Click to expand...

#define apple  0b1111110
#define banana 0b1111101
#define orange 0b1111011
#define peach  0b1110111

    return = somefunction(apple&pear);

Ian Rogers said:

Wow.. Harsh school!!

Click to expand...

Pommie said:

I hate to bring this up as it confuses the situation. Some C code defines constants as binary then ANDs them together to pass to a function as a single byte.
E.G.

Code:

#define apple  0b1111110
#define banana 0b1111101
#define orange 0b1111011
#define peach  0b1110111

    return = somefunction(apple&pear);

Note also that C uses && and || when doing comparison operations.

Mike.

Click to expand...

ericgibbs said:

hi C,
OSH list:
E

Dim tens As Byte
Dim units As Byte
Dim x As Byte

If tens > units Then
x = 0
Endif

If tens < units Then
x = 1
Endif

If tens <> units Then
x = 2
Endif

If tens = units Then
x = 3
Endif

If tens >= units Then
x = 4
Endif

If tens <= units Then
x = 5
Endif

If tens = > units Then 'OSH will not accept the '=' sign first
x = 6
Endif

If tens = < units Then 'OSH will not accept the '=' sign first
x = 7
Endif

Click to expand...

camerart said:

I have a line with IF ((x AND y) AND (NOT (x AND z )))
How is this written in Oshonsoft?
EDITED!
C.

Click to expand...

Ian Rogers said:

I gave that answer in post #15

Click to expand...

jjw said:

can be written in Oshonsoft:
If res2 > 0 And res2 > 0 Then

Click to expand...

dim aa as byte
dim ab as byte
dim ac as byte
dim res1 as byte
dim res2 as byte

res2 = aa and ab
res 1 = aa and ac
res1 = not res1

if res2>0 and res1>0 then
   PORTB = 255
else
   PORTB = 0 
endif

end

Ian Rogers said:

That seems to work... when aa = 0xAB result1 is positive and result3 becomes 255... If I change aa to 0 then result1 = 0 so result3 = 0

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