S spirosd New Member Feb 22, 2006 #2 Code: main(int argc, char *argv[]) { ...... } Now, the separators for argv are os dependant but typically they are tabs or spaces so one, two, and three => four strings one,two, and three => three strings If you want number parameters you would convert the string into a number using atoi() atof() ... HTH Spiros
Code: main(int argc, char *argv[]) { ...... } Now, the separators for argv are os dependant but typically they are tabs or spaces so one, two, and three => four strings one,two, and three => three strings If you want number parameters you would convert the string into a number using atoi() atof() ... HTH Spiros
M MikeHibbett New Member Feb 22, 2006 #3 Can you explain your question a different way? It is just that argv[1] is already a char array. What is it that you wish to do? Can you give us an example of your problem? Mike.
Can you explain your question a different way? It is just that argv[1] is already a char array. What is it that you wish to do? Can you give us an example of your problem? Mike.
akg New Member Feb 27, 2006 #4 danielsmusic said: is this posible, looking on google turned up nothing. Click to expand... argc contains the nof arguments passed and argv[0]...argv[n] contains the different arguments.and itself char*
danielsmusic said: is this posible, looking on google turned up nothing. Click to expand... argc contains the nof arguments passed and argv[0]...argv[n] contains the different arguments.and itself char*
danielsmusic New Member Mar 18, 2006 #5 well i wrote this fuction that needs a char array to work but just passing argv[2] doesnt work i wont compile i sayes it cannot convert it
well i wrote this fuction that needs a char array to work but just passing argv[2] doesnt work i wont compile i sayes it cannot convert it