c++ convert argv[1] to a char array

danielsmusic

New Member

• Feb 21, 2006

• #1

is this posible, looking on google turned up nothing.

 

S

spirosd

New Member

• Feb 22, 2006

• #2

Code:

main(int argc, char *argv[])
{
 ......
}

Now, the separators for argv are os dependant but typically they are tabs or spaces so

one, two, and three => four strings
one,two, and three => three strings

If you want number parameters you would convert the string into a number using atoi() atof() ...

HTH
Spiros

 

M

MikeHibbett

New Member

• Feb 22, 2006

• #3

Can you explain your question a different way?

It is just that argv[1] is already a char array.

What is it that you wish to do?

Can you give us an example of your problem?

Mike.

 

akg

New Member

• Feb 27, 2006

• #4

danielsmusic said:

is this posible, looking on google turned up nothing.

Click to expand...

argc contains the nof arguments passed and argv[0]...argv[n] contains the different arguments.and itself char*

 

danielsmusic

New Member

• Mar 18, 2006

• #5

well i wrote this fuction that needs a char array to work but just passing argv[2] doesnt work i wont compile i sayes it cannot convert it

 

Styx

Active Member

• Mar 18, 2006

• #6

whats the code?