Hello,
I would like to know how can i calculate base current when base is directly connected to emittor/collector?
Ir1 = 600uA Ib= 2uA
Spice says...
I though current would be splitted in half. But it isnt.
thanks
I'd expect it to be the collector current divided by the hFE at that current, as long as the overall current is within the transistor continuous rating.
eg. For an hFE of 200, base current 1/200th the collector current.
I suspect that while it's nice in theory, in reality it will be FAR different - when you operate transistors near saturation point the gain drops off considerably.
However, why would you want to know? - you're wiring the transistor as a diode - so there is no base and no collector.
It was strange to me. I supposed that current would flow symetricaly in two different paths (splited in halfs). I am learning at my own, sometimes I just stare blankly into a book... Then i ask here =)
With the base connected to the collector then the emitter current is exactly the same as the collector.
With the base connected to the emitter then the transistor is turned off and does not conduct any current.