Hi again,
If the speed decreases then the area of the field swept out by a length
of wire in a time dt decreases which in turn causes a decrease in the voltage.
Also, the voltage and resistance is a better way of looking at this
problem anyway. This is the other problem i hadnt talked about in the
previous thread
I've included a graph to compare the two different views on charging
the capacitor. The blue indicates the voltage charged by a constant
current charging source, and the green is charging by a generator
that puts out a max of 24v and has an internal resistance of
24/27 ohms. The respective energies are shown in violet and orange.
We can see it takes a lot longer to charge than with a constant
current charging source as you were presuming. This will be more
realistic, although a good test would be in order before buying parts.
It takes roughly 3 to 4 times longer to reach the same energy level.
Get a smaller cap and test the time it takes to charge to 24v (or whatever
that generator puts out) and we can do a more precise calculation
after getting the results of that test.
For example, how long does it take to charge a 1F cap under the
exact conditions that will be used for the final design.