To reduce the 190Ω to 100Ω equivalent, add a 210Ω resistor in parallel with the fuel sender.
The main negative to that, is it will make the gauge reading somewhat nonlinear.
The LTspice simulation (below) of the two resistors in parallel shows the parallel resistance (vertical scale) versus the sensor resistance (horizontal scale).
As you can see, a tank half-full sensor reading (90Ω) gives a parallel value of 63Ω to the gauge, whereas 50Ω is gauge half scale.
The half-full gauge reading will occur at a sensor value of 65.8Ω or about 35% full.
So the gauge will read some high when the tank is between full and empty.
The full and empty readings will be okay, of course.
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