windozeuser
Member
Hello board, I ran into a relatively (well I thought) simple problem, but I think I'm going brain dead.
**broken link removed**
The above circuit has a 100 ohm, and a 70 ohm(68 was closest) resistor in series with a resistor(Rx) in parallel across points A and B. There must be 3V at points A and B.
using ohms law
The series resistors must drop 17 volts
I = 17V/170ohms
I = 0.1 (100mA)
so Rx = 3/0.1 = 30 ohms?
Am I correct, please help
Thanks
**broken link removed**
The above circuit has a 100 ohm, and a 70 ohm(68 was closest) resistor in series with a resistor(Rx) in parallel across points A and B. There must be 3V at points A and B.
using ohms law
The series resistors must drop 17 volts
I = 17V/170ohms
I = 0.1 (100mA)
so Rx = 3/0.1 = 30 ohms?
Am I correct, please help
Thanks