As drawn your circuit will have a few issues. You have 230 VAC applied. With a 1,000 Ohm load your current would be about 230 mA. The power dissipated by the load would be I * E or .230 * 230 = about 53 Watts so in reality you would need a 1,000 Ohm 100 Watt resistor for your load. That said the voltage across your load resistance would still be the applied voltage of 230 VAC. Obviously any short in the line, depending on your supply current, will trip the breaker and the voltage across the load will drop to zero,
I am not seeing that in your drawing? Additionally doing this with low voltage DC verse AC would be much simpler.
Ron