2000uA is only 2mA, which is too low a range, and the voltage drop across the meter is likely to stop it working.
Stick a croc clip lead across the two bare copper wires you can see in the picture, to ensure that the phone works then (proving the adaptor you've made is working).
No - aluminium doesn't solder (with normal tin/lead solder) - so you don't ever try to solder it. You can get special aluminium solder, but I've no idea if that would solder to copper or not?.
And yes, that looks horrible - the solder around the wire is floating above the aluminium - there's no actual joint.
with two layers of bean can, the battery wouldn't go in the holder
In post #14 the picture shows the red and black power wires soldered to the battery holder. Why not just unsolder one of those wires and connect your current meter between the end of the wire and the battery holder connection from which it was unsoldered ?
In post #14 the picture shows the red and black power wires soldered to the battery holder. Why not just unsolder one of those wires and connect your current meter between the end of the wire and the battery holder connection from which it was unsoldered ?
Put the meter on Vdc and it measures 2.29V.
Put it on Adc (whatever range) and nothing. On the meter, or the phone.
I can only suspect that the NiMH charging circuit is detecting the increased resistance and switching the battery out of the circuit.
Another interesting thing is that the only chip I can identify -- an FM24C16B FRAM chip visible on the circuit boad just below the silver can labelled cs 220 4V
-- is speced to run at 4.5v - 5.5v. Presumably, this is where the 40 number memory and redial etc. are stored. These can be viewed and edited when on battery power. Which to me suggests that there must be a boost converter in there somewhere?
Also, do you guys know what the black blob (with a letter K) that covers/hides the main chip is? It is literally rock hard. I tried to cut into it with a penknife, and it blunted the tip, without leaving a mark on the blob.
Also, do you guys know what the black blob (with a letter K) that covers/hides the main chip is? It is literally rock hard. I tried to cut into it with a penknife, and it blunted the tip, without leaving a mark on the blob.
Another interesting thing is that the only chip I can identify -- an FM24C16B FRAM chip visible on the circuit boad just below the silver can labelled cs 220 4V
Also, do you guys know what the black blob (with a letter K) that covers/hides the main chip is? It is literally rock hard. I tried to cut into it with a penknife, and it blunted the tip, without leaving a mark on the blob.
It's a COB (Chip On Board), nothing you should be concerned with, you can't buy it, and you can't replace it - the entire PCB is effectively the chip, with the silicon wafer covered in epoxy.
It's a COB (Chip On Board), nothing you should be concerned with, you can't buy it, and you can't replace it - the entire PCB is effectively the chip, with the silicon wafer covered in epoxy.
To clarify Nigel's answer, something like this (obviously not the same PCB).
A bare silicon die, bonded directly to the PCB rather than bonded in to a carrier package and encapsulated in that, like a conventional IC.
To clarify Nigel's answer, something like this (obviously not the same PCB).
A bare silicon die, bonded directly to the PCB rather than bonded in to a carrier package and encapsulated in that, like a conventional IC.
No, the charging circuit will almost certainly be crude, nasty, and really horrible - probably just a single resistor.
I explained the likely reason in post #44, you had the meter set to much too small a range, so much too high a resistance. However, this assuming the 'soldered' connections to the foil are working (which is dubious) and that the foil itself is making good electrical contact.