Hi,
I see a circuit of difference amplifier where the reference is set to 10V (the rest of the circuit require a bipolar supply , therefore the reference) . I know the transfer function of the difference amplifier when referenced to GND , but what is the ckt behaviour in the attached image . When we reference it to 10V , is it the same as before Vout=((V2-V1)(Rf/Rin) , hope V2,V1,Rf,Rin are understood . And this time the ckt is expected to get a VCC of 14V? , is this correct.
Thanks
-Adi
I see a circuit of difference amplifier where the reference is set to 10V (the rest of the circuit require a bipolar supply , therefore the reference) . I know the transfer function of the difference amplifier when referenced to GND , but what is the ckt behaviour in the attached image . When we reference it to 10V , is it the same as before Vout=((V2-V1)(Rf/Rin) , hope V2,V1,Rf,Rin are understood . And this time the ckt is expected to get a VCC of 14V? , is this correct.
Thanks
-Adi
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