Hello,currently i'm designing single ended to differential signal converter.I use differential pair with emitter resistor.In order to get the Q-point,i have to know about my Vce cutoff point.But, the problem is i'm not sure what is my Vce cutoff point.Below is my attachment about my circuit~
Thanks~
i use measurement probe to get those yellow boxes.How to know that the maximum of the input signal can be applied to avoid the distortion to occur?because the assignment requests us to find out the reason behind~and what do you mean a constant current source emitter drive?
thanks
i use measurement probe to get those yellow boxes.How to know that the maximum of the input signal can be applied to avoid the distortion to occur?because the assignment requests us to find out the reason behind~and what do you mean a constant current source emitter drive?
thanks
my gain is 0.5 and actually 900ohm and -5V is my design of current source~and got any equations can be used to calculate and prove that when it reaches the maximum input,the output signal will start to distort?because when i do my simulation, i found out that when my input is 2.7Vppk, the output signal start to be cutoff.
Thanks
my gain is 0.5 and actually 900ohm and -5V is my design of current source~and got any equations can be used to calculate and prove that when it reaches the maximum input,the output signal will start to distort?
Thanks
hi,
in order to get the maximum swing,normally the Q-point of the circuit will be on the center of the DC load line,but the problem is i don't know how to calculate my Vce cutoff point,thus i cant determine where is my center of the DC load line.
Now,i'm not sure that the circuit i designed,its Q-point is on the center on DC load line or not.