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Peter M said:Thanks for the reply, but need a clarification: if I want to create a DC output of 16V from an AC source using a single diode, do I begin with
8V AC?
This gives the peak voltage. Also, as Audio said, there will be a ripple and its amplitude will depend upon the load resistance and the capacitance of the filter capacitor. The voltage drop across the diode is also a function of its slope resistance and the current through it.evandude said:DC output = (AC voltage * 1.414) - diode voltage drop