AnthonyR23
New Member
Hi, I am working on a unit for my electro- course... I have the answer but am having trouble working out this question.... if someone could help that would be awesome!!
Question:
If a Weston-type ammeter with a coil resistance of 12.6 ohms has a shunt resistor of 1.92 ohms, which is dissipating 930 mW of power, how much current is going through the meter coil?
Answer:
106.1 mA
I am trying to work this out... but am having a lot of trouble...
Formula Shunt Current / Meter Current = Meter Resistance / Shunt Resistance
Thanks!! This is the one question that is holding me up... before my exam...
Question:
If a Weston-type ammeter with a coil resistance of 12.6 ohms has a shunt resistor of 1.92 ohms, which is dissipating 930 mW of power, how much current is going through the meter coil?
Answer:
106.1 mA
I am trying to work this out... but am having a lot of trouble...
Formula Shunt Current / Meter Current = Meter Resistance / Shunt Resistance
Thanks!! This is the one question that is holding me up... before my exam...