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fr = 1/(2π√LC)
Does anybody know how to rearrange this formula to find L? having some trouble doing it.
I've tried alot of methods and im pretty sure one of them is right what i basically need is clarification before i put it onto paper.
I've tried alot of methods and im pretty sure one of them is right what i basically need is clarification before i put it onto paper.
Fr = 1/ 2pi sqrtLC
2pi x fr = 1/sqrtLC
(2pi x fr)^2 = 1/LC
(2pi x fr)^2/C = L
or
1/Fr = 2pi sqrtLC
1/Fr(2pi) = sqrtLC
1/ (fr(2pi))^2 = LC
1/ C(fr(2pi))^2 = L
Take the 1 over so it becomes x making it irrelevent then taking the C over to make it a division.
Would it not be the same as anything x1 is the same figure.
L = (2pi x fr)^2 / C
Take the 1 over so it becomes x making it irrelevent then taking the C over to make it a division.