Finding the maximum number of outputs

[mgr1397]

I'm wondering how iti s possible to find the maximum number of bjt current mirrors you can put together with an error that does not exceed 10% and β= 100.

 

[lebevti]

interesting question...isn't it where the more current mirrors u put in parallel, the less the error is?

i would say 10% probably needs 1 or 2 max

 

[Jony130]

The mathematical answer is 10.11 BJT's So I think that 10 is the answer

Iref/Io = 1/ ( 1 + (1 + n)/β )

n - number of outputs


Iref/Io = 1/ ( 1 + (1 + 10)/100 ) = 1/1.11 = 0.9009