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Fourier Analysis BFSK

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derick007

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If y1(t) has the f1 frequency and y2(t) has the f2 frequency, in a BFSK system, then does the Fourier Transform (FT) of y1(t)+y2(t) equal :

FT ( y1(t) + y2(t) ) = FT ( y1(t) ) + FT ( y2(t) ) :oops:
 
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