@donniegunz
no problem. i didn't know what is your experience of comfort level, i read 'simple' in the first post so i offered the simplest possible solution. using opamp has other advantages, like ability to drive smaller impedance loads etc.
as crutschow noted, your oscillator does not produce perfectly symmetrical signal so he is correct that AC after capacitor would not have absolutely equal amplitudes for positive and negative part of period.
the slight assymetry is due fact that in this oscillator capacitor is charged through R1+R2=71.9k, but discharged only through R2 (68k).
so you get square wave with duty cycle that is 48.6% because
68/(68+71.9)=0.4860617... (on time is 48.6%, off time is 51.4%).
this 1.4% in duty corresponds to some 70mV offset. (integrals or areas of positive and negative halfperiod are equal, so if one pulse is wider, it will be lower in amplitude and the other way arround).
i seriously doubt that your application would suffer because you get +5.07 to -4.93V insted of +5V...-5V.
even this can be adjusted by adding biasing circuit of two resistors or simply one potentiometer (in which case you can adjust DC offset to your liking). for example one side of potentiometer could connect to +5V, othr to -5V and wiper to output (after coupling capacitor).