fouadalnoor
Member
Hello guys, I am studying for my physics exam and got stuck at this past paper question on gauss's law (attached).
I am probably wrong, but would the solution to i) be:
C = Q/V
V = E*D
Since ∫E*dA = Q/εo
Then:
EA = Q/εo, thus E = Q/(Aεo) , where A = 4Πr^2
Now V = QD/(4Πr^2)
D = b-a
thus:
C = (4Πr^2εo)/(b-a)
ii)
As b tends to infinity
C = 0 F?
Hope you guys can help!
I am probably wrong, but would the solution to i) be:
C = Q/V
V = E*D
Since ∫E*dA = Q/εo
Then:
EA = Q/εo, thus E = Q/(Aεo) , where A = 4Πr^2
Now V = QD/(4Πr^2)
D = b-a
thus:
C = (4Πr^2εo)/(b-a)
ii)
As b tends to infinity
C = 0 F?
Hope you guys can help!
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