necessarynoize
New Member
i have 2 74ls93...i want make 1 to be divisible by 8 and the other1 by 5..but i dnt know which 1 to connect..
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hi,necessarynoize said:i have 2 74ls93...i want make 1 to be divisible by 8 and the other1 by 5..but i dnt know which 1 to connect..
ericgibbs said:hi,
THe 74LS193 is binary counter so you would use the Qc output, for a count of 8, of the first LS193 to drive the second LS193.
For a count of 5 you would need to detect when the second LS193 has counted to 6 say, thats Qb and Qc outputs, when this count of 6 is detected it drives the clear pin on the second LS193.
An 'AND' gate would be used to detect Qb and Qc.
If the the count rate is low, then a couple of signal diodes and a resistor could make the 'AND' gate.
As the the LS193 is a synchronous counter there are a number of ways to detect and restart for a count of 5.
Do you follow this OK.?
necessarynoize said:i really follow but iam trying to do a fruit machine project..i got a 555 timer feeding in to 3 74ls93. 1 is divisible by 9 so i managed to get that to work which then feeds to the 74ls47 then to the seven segment display..but am stuck on how to make the remaining 2 1 to be divisible by 8 and the other1 by 5....help plz..