Holtek encoder HT12E, help please

My understanding of the Holtek data sheet for the encoder HT12E is as follows:-

An "information word" is a 12 bit "pilot" followed by 12 bits of "data" where the data maybe either 8 bits address + 4 bits data or 12 bits address.

For an oscillator frequency of 3 kHz, the data rate transmitted is 1 ms/bit.

So the 24 bit word (pilot + data) is sent in 24 ms.

If the TE pulse is < 24ms, then 4 words are sent, ie. 24 bits * 4 = 96 bits taking 96 ms.

So if the data sent was (using Hex for simplicity) A9C, then the encoder would send Pilot + A9C, Pilot + A9C, Pilot + A9C, Pilot + A9C and then stop.

If the TE pulse is > 24ms but < 96 ms, say 30 ms, then 8 words are sent, ie. 24 bits * 8 = 192 bits taking 192 ms.

Is this correct?

Can anyone help me with this please?

ljcox said:

For an oscillator frequency of 3 kHz, the data rate transmitted is 1 ms/bit.
So the 24 bit word (pilot + data) is sent in 24 ms.

Click to expand...

If I understand the HT12A/E datasheet(page 7) correctly, there is an additional sync pulse, with length 333us(1/3 bit or one Fosc cycle) after the pilot and before actual data begin.

This would add up to 24.333ms total time for sending a word.

Thanks. I assume you agree with the rest then.