Imagine constant current nimh charger, more than one slot
1) AC to DC SMPS output 3v3/5V?
2) If its constant current than transistor is regulated by op amp (variable resistance) or for each slot there is buck converter with current and voltage feedback.
* if current is regulated by transistor than charger is damn unefficient.
If its charged with pulse current than it cant be called continous, its average current
How its done in standart battery chargers from wallmart?
thansk
I use an OPUS charger that does 4 cells ( a mix of 4 AA or AAA) or a mix of (two C and D) with adapters. It has a display for each battery and mutiple selction of charging currents, Some test modes for capacity, some charging modes including complete discharge frst. Voltage and mAh. It's not too expensive. i.e about $40.00 USD. It can do Li-ion, Ni-Cd and N-mH without telling it the battery type. it's not too expensive.
This one does not do battery packs.
There are specific charging IC's.
Each type of battery has a different charging profile. Packs have battery balancing circuits.
The simplest method is just a voltage regulator plus a resistor to feed each cell slot.
The current drops off as the cell approaches full charge voltage.
As long as it's less than 1/10th the cell capacity rating when the cell reaches full charge, it's OK as a "14 Hour" charger. If less than 1/20th capacity (eg. 100mA for a 2000mAH cell) it can be left on for long periods.
Fast chargers must monitor the cell voltage and drop down to a trickle charge once the cell is full, or near so.
The battery is relatively low impedance, so the voltage can be measured moderately accurately while on charge.
If it reaches the voltage limit the current must be reduced anyway.
No. The charge voltage across a NiMH battery will rise during charging, and then start to fall when it's fully charged. Monitor the charge voltage for this inflection point.
The temperature of the battery will quickly rise when it's fully charged.
In the early days of NiMH batteries, the company I worked at was using a battery pack with 8 D cells. What we didn't know at the time was that the manufacturer was having difficulty making D cells – a large number of them experienced early failures. With 8 cells in the packs, failure was too common and customers unhappy. The task fell to me to develop a test/exercising station for the battery packs. As I recall, we exercised six or eight packs at a time through about 4 charge/discharge cycles in 24 hours. I looked at a lot of charge/discharge curves until the manufacturer got their act in order.
The battery is relatively low impedance, so the voltage can be measured moderately accurately while on charge.
If it reaches the voltage limit the current must be reduced anyway.
I tried that but voltages change by .3 volts when voltage source is disconected.
If i need to charge battery fully then i need to check for dV drop. What if i want to charge battery on exact voltage? Then i need to check voltage by turning off charging?
No, simply monitor it while charging - as visitor also mentioned, it's normal to monitor the temperature as well.
All the batteries we change are in packs with current fuses, thermal fuses, and thermistors, and charged correctly by specific charger IC's (usually the LTC4011) - yet they still have a pretty short life span.
If i need to charge battery fully then i need to check for dV drop. What if i want to charge battery on exact voltage? Then i need to check voltage by turning off charging?
You should just reduce the current down to a safe trickle level once the voltage passes around 1.45V (or if the cells start to warm up noticeably).
The voltage drop only really matters if you are trying to fast charge right to the limit, which is not normally required.
Note from Visitor's graph that the drop off only happens after the nominal 100% charge point.
Reducing the charge current earlier keeps the temperature and pressures down.
Its easier, no doubt about it. But not "represantitive" ( funny when i say that ) . Also such high resistance limit maximum current to under 1A. Btw thanks anyway
Its easier, no doubt about it. But not "represantitive" ( funny when i say that ) . Also such high resistance limit maximum current to under 1A. Btw thanks anyway