I'm assuming that the lamp is 24V 10W (you didn't mention it, but labelled the supply to the chip as 24V).
The formula for power is W=V*I, transposing this you get I=W/V, which is 10/24=0.42A. The easiest way to solve your problem would be to parallel two (or more) of the gates, two would give you 600mA, three 900mA, and so on - bearing in mind the total limitations of the chip.
If you want to add a series resistor (and reduce the light output from the lamp), the only two formulas you need are:
V=I*R
W=V*I