I believe there should be a positive current feed to bias pin 1 of IC2-A.
Q2 looks like E is connected wrong. E should connect to V+, C to R12 ,then to IC2-A pin 1.
Actually, now that I think about it, Q2 may not be needed.
Checking all voltages on op amp and transistors shows that only different value is the PNP transistor collector voltage. Which is odd since base and emitter voltages are same.
I know the LM13700 is not damaged since there is 20K resistor between Q2 and its amp bias pin and its voltage is always around -11 volts. I can change the connections of pin 1 and pin 16 to see that first VCA also works on other side and faulty one moves to first one. Also the linear mode works just fine on both of them. There is something wrong with Q2 or IC-1C connections. Since I checked Q2 like 20 times I can't say what is the problem with it. Will check it again.The bias current is supposed to be sourced from 0V; the IC internal bias current circuit operates at about two diode drops from negative supply.
The weird Q2 configuration is a logarithmic converter, common (in some form) in synths.
Double check all the resistor values??
The Q2 and OTA bias input circuits are current control, not voltage, so there should not be much voltage change at the amp control input pin over the control input range.
If it reaches even 1.5V above the negative supply, the IC may already have been damaged, or be faulty.
See the amp bias input circuit, bottom left in the diagram; two base-emitter junctions connect it to negative power. Anything more than 2mA in to that pin can damage or destroy it.
View attachment 138498
I see so that one has an extra pot between inverting and non inverting pins of the lm13700 and a 4.7k resistor connected to negative supply at the output. I wonder if I need them.
Clipping was from missing R16 and fixed. My input is 10V peak to peak from VCO.atferrari already mentioned the suspicious connection of Q2. That's not the best way to make your transfer function logarithmic.
Q2 will act like a 5 volt Zener diode when the voltage on its base reaches...5 volts.
From the Fairchild 2N3906 datasheet:
View attachment 138509
Is the clipping level near +5VDC?
That log converter is just too unreliable. I fixed the problem by brute forcing different transistors and yet even though now VCA works the one that uses bc548 and bc558 works better (it got higher maximum output volume) than the one I fixed with 2n3904 and 2n3906. But I can't afford to fiddle more with it since it will probably stop working if I do.atferrari already mentioned the suspicious connection of Q2. That's not the best way to make your transfer function logarithmic.
Q2 will act like a 5 volt Zener diode when the voltage on its base reaches...5 volts.
From the Fairchild 2N3906 datasheet:
View attachment 138509
Is the clipping level near +5VDC?
If I decrease the resistance of the 20K resistor thats connected to Amp bias and let more current flow through it. Will it increase the maximum output voltage. Because this thing operates with current instead of voltage like Op Amps I am having trouble understanding it. The transistor pairs are not making it open enough because random silicon differences I think.The bias current is supposed to be sourced from 0V; the IC internal bias current circuit operates at about two diode drops from negative supply.
The weird Q2 configuration is a logarithmic converter, common (in some form) in synths.
Double check all the resistor values??
The Q2 and OTA bias input circuits are current control, not voltage, so there should not be much voltage change at the amp control input pin over the control input range.
If it reaches even 1.5V above the negative supply, the IC may already have been damaged, or be faulty.
See the amp bias input circuit, bottom left in the diagram; two base-emitter junctions connect it to negative power. Anything more than 2mA in to that pin can damage or destroy it.
View attachment 138498
Assuming he means Q1?, then the transistor goes directly from 12V (at the collector) to ground (at the emitter) via two paralleled Vbe junctions - so if the base goes positive very far you could certainly overheat Q1 as there's nothing to limit current.Are the transistors you are using bought from a proper supplier, or some unknown source devices?
It should not be possible for the 2N3904 in that circuit to overheat. I can only guess it's a faulty / reject one or remarked device with different pinouts..
Do you have a transistor tester? They are invaluable for checking pinouts and that components are OK.
Look for something like this on ebay:
Transistor Tester Diode 328 ESR/PNP/NPN L/C/R Graphics MOS Transistor Tester* | eBay
Find many great new & used options and get the best deals for Transistor Tester Diode 328 ESR/PNP/NPN L/C/R Graphics MOS Transistor Tester* at the best online prices at eBay! Free delivery for many products.www.ebay.co.uk
I have that exact same device. I tested them before putting them on the circuit. Transistors are bought from legit local shops. They only cause problems when I try to build that specific circuit.Are the transistors you are using bought from a proper supplier, or some unknown source devices?
It should not be possible for the 2N3904 in that circuit to overheat. I can only guess it's a faulty / reject one or remarked device with different pinouts..
Do you have a transistor tester? They are invaluable for checking pinouts and that components are OK.
Look for something like this on ebay:
Transistor Tester Diode 328 ESR/PNP/NPN L/C/R Graphics MOS Transistor Tester* | eBay
Find many great new & used options and get the best deals for Transistor Tester Diode 328 ESR/PNP/NPN L/C/R Graphics MOS Transistor Tester* at the best online prices at eBay! Free delivery for many products.www.ebay.co.uk
The lower ones are PNP, drawn upside down (just to confuse things), so the only base current should be from the 120K resistor to -12V??Assuming he means Q1?, then the transistor goes directly from 12V (at the collector) to ground (at the emitter) via two paralleled Vbe junctions
Thats odd because I saw it swing down from -8V to positive 8V with pots movement and while doing that transistor started heating up. Sometimes CV input and CV off set pot doesn't effect its output, sometime it does. It is a total mystery.Also the opamp output should never be more than a few hundred millivolts as it's "gain" is around 0.02
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