Hi guys,
Sorry but I came across to a problem when I was studying about Boost converters.
The Problem is That I am not able to properly undrstand what will happen to the voltage of a an inductor when the voltage across it is oppened immediately.
considering the below circuit the circuit A is understandable to me and it shows that the inductor is charging up and storeing the energy in its magetic field,
But Why while we open the key (the circuit B) the voltage going through the diode to the capacitor is going to be much higher than the input voltage?
I know that the diode allows the stored current to go to the cap while the key is opened and of course does not allow it to come back at other conditions but my question is tha I want to know if the inductor itself generates a voltage which is higher than the input voltage? If so does this voltage reaches to the MAX at just one cycle?
I tried it practically to see what will happen. I used an 33mH inductor and a 1N4007 diode and a 220uF/500V electrolyte capacitor. I noticed each time I turn the key on and then off just a rather small incasement will happen to the cap voltage. the input voltage was 10V DC and I could cause the capacitor voltage to reach to the 20V DC by then time switching or more.
Before doing this test I thought that by just switching on and off for once the inductor will generate the MAX posibble voltage for the cap but After doing the test I am not able to see what does happen and of course why...?
Thanks for any help
Sorry but I came across to a problem when I was studying about Boost converters.
The Problem is That I am not able to properly undrstand what will happen to the voltage of a an inductor when the voltage across it is oppened immediately.
considering the below circuit the circuit A is understandable to me and it shows that the inductor is charging up and storeing the energy in its magetic field,
But Why while we open the key (the circuit B) the voltage going through the diode to the capacitor is going to be much higher than the input voltage?
I know that the diode allows the stored current to go to the cap while the key is opened and of course does not allow it to come back at other conditions but my question is tha I want to know if the inductor itself generates a voltage which is higher than the input voltage? If so does this voltage reaches to the MAX at just one cycle?
I tried it practically to see what will happen. I used an 33mH inductor and a 1N4007 diode and a 220uF/500V electrolyte capacitor. I noticed each time I turn the key on and then off just a rather small incasement will happen to the cap voltage. the input voltage was 10V DC and I could cause the capacitor voltage to reach to the 20V DC by then time switching or more.
Before doing this test I thought that by just switching on and off for once the inductor will generate the MAX posibble voltage for the cap but After doing the test I am not able to see what does happen and of course why...?
Thanks for any help
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