throbscottle
Well-Known Member
Ok so I've finally got back to doing some work on my little bench dmm project. I was reviewing the help I've received on here so far (thanks again folks ) and puzzling over mixed power supply requirements - when I discovered fully differential op-amps, which I think makes a very good solution.
I can't build anything to test yet because all my electronic stuff is still packed away following the house move, and is likely to stay packed for a couple of months at least.
I've drafted a notional circuit (attached) which I think achieves what I want:
* A permanent un-switched first stage of the input divider between the meter input and any input circuit - so the input is always divided by at least 10 - this means the input voltage will never exceed the ratings for the reed relays I'm using (unless Something Really Bad happens)
* An amplifier to bring the voltage back up and give more practical scaling
* Differential input to the ADC
* Accommodate mixed split/single supply requirements
* Work with + and - inputs
The adc block on the drawing is a dummy just to show how the adc will be connected.
The Vocm input on the fully diff. amp is used to set the mid point for it's outputs to half the adc's reference voltage, so the adc can see both positive and negative inputs.
This particular adc gives best accuracy when Vref=Vcc.
The first op-amp is to give a very high impedance input - I was originally looking at CA3160 (thanks ron)
The second op-amp has differential outputs, but is connected with a single sided input.
The analogue supply voltage is + and - to accommodate + and - inputs
The analogue supply voltage is quite high (yeah ok I need to lower that!) to ensure linearity and for good power supply rejection
The digital supply 0v is connected to analogue 0v at the PSU
I haven't shown any protection.
It simulates OK, but I have some questions:
In principle, is this a good design (ie, what is wrong with this circuit)?
I'm now confused about the input voltage I should be allowing to the adc. My previous situation was that the "-" input would be fixed at +2.5v, so the "+" input could go between +5v and 0v, so the range was -2.5v to +2.5v. With this new arrangement, it looks as though I can use adc differential input equal to the full reference voltage. Is this true? Relevant spec on page 3 of the data sheet (attached). I'd really appreciate someone else looking at this, because all this is still pretty new to me.
Am I better to use the first op-amp as the gain stage, with the fully diff amp having a gain of 1? Or leave it as it is?
Any beginner mistakes I've made?
Thanks in advance
I can't build anything to test yet because all my electronic stuff is still packed away following the house move, and is likely to stay packed for a couple of months at least.
I've drafted a notional circuit (attached) which I think achieves what I want:
* A permanent un-switched first stage of the input divider between the meter input and any input circuit - so the input is always divided by at least 10 - this means the input voltage will never exceed the ratings for the reed relays I'm using (unless Something Really Bad happens)
* An amplifier to bring the voltage back up and give more practical scaling
* Differential input to the ADC
* Accommodate mixed split/single supply requirements
* Work with + and - inputs
The adc block on the drawing is a dummy just to show how the adc will be connected.
The Vocm input on the fully diff. amp is used to set the mid point for it's outputs to half the adc's reference voltage, so the adc can see both positive and negative inputs.
This particular adc gives best accuracy when Vref=Vcc.
The first op-amp is to give a very high impedance input - I was originally looking at CA3160 (thanks ron)
The second op-amp has differential outputs, but is connected with a single sided input.
The analogue supply voltage is + and - to accommodate + and - inputs
The analogue supply voltage is quite high (yeah ok I need to lower that!) to ensure linearity and for good power supply rejection
The digital supply 0v is connected to analogue 0v at the PSU
I haven't shown any protection.
It simulates OK, but I have some questions:
In principle, is this a good design (ie, what is wrong with this circuit)?
I'm now confused about the input voltage I should be allowing to the adc. My previous situation was that the "-" input would be fixed at +2.5v, so the "+" input could go between +5v and 0v, so the range was -2.5v to +2.5v. With this new arrangement, it looks as though I can use adc differential input equal to the full reference voltage. Is this true? Relevant spec on page 3 of the data sheet (attached). I'd really appreciate someone else looking at this, because all this is still pretty new to me.
Am I better to use the first op-amp as the gain stage, with the fully diff amp having a gain of 1? Or leave it as it is?
Any beginner mistakes I've made?
Thanks in advance