LCD without zero

A

aduri

New Member
Hello,
This code (Mikrobasic) converts an analogical value in a binary for a radio frequency control.


This's the code:


This is my problem:


When the value is lower than 10 (e.g. 9), I'd like the LCD to visualise the number 09
I tried with the IF code, but it doesn't work.

Ciao
Antonio
 
Last edited:
Can you change the second if to,
Code: 
if (ValoreAdc1<10) then ValoreADC=9 '
end if

Mike.
 
Are you trying to pad single digit numbers with a leading '0'? A little more code and sure we can help.
 
Manily needed is:

bytetostr
LCD_out

we need to see how these work to show you how to pad it.

Also i assume that "ValoreAdc1" is normal DEC and not BCD.

so :

Code: 
cod_fine:
    byteAdcbin1 = Dec2Bcd16(ValoreAdc1) ' conversione da decimale a binario
    if (ValoreAdc1 == 0) then
        portb=255 'led or contraves on pins 32 to 40
    else
        if (ValoreAdc1 <= 99)
            then portb = not byteAdcbin1
        end if
    end if

    if (ValoreAdc1 >= 100) then
        ValoreAdc1 == 99 '
    end if
    if (ValoreAdc1 <= 9) then
        LCD_out(1,11,"0") 'wouldnt this have to be [b]LCD_out(1,09,"0")[/b]
    end if                'i say the above because you want the 0 before 
                          'the 10th character aka 9th character

    bytetostr(ValoreAdc1,txt1)
    LCD_out(1,10,txt1)    'assuming that this is the 10th character on screen

I changed the if = to if == also some if < to if <=

also since this is basic i dont know much really but should a single char be in single quotes '0' not "0", if all failes try 0x30 :

LCD_out(1,09,'0') or LCD_out(1,09,0x30) should be the same thing a (0)
 
Last edited:
Thank you,
I solved with this code.


Code: 
bytetostr(ValoreAdc1,txt1) 
       if (ValoreAdc1<10) then txt1[1] = "0" 
       end if 
  LCD_out(1,10,txt1)



Ciao
Antonio
 
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