Hi... I have constructed the following circuit which runs fine on 9V. The circuit responds to light and dims/brightens the LED.
Using this concept, I would like to put this circuit in line with a 120V outlet and power strip and essentially use it as a control valve.
Based on the light intensity, only so much current will flow from the wall socket through the circuit and to the power strip. If the light is totally lit, the full AC current runs through the circuit over to the power strip. As the light dims/increases, the AC current is also diminished/increased.
I need help in modifying the circuit to do this extra "control valve" process.
I went back to the url and found their simplist example. It is hard to read but here is the one they referenced. I'm assuming that instead of the 185K pot, I would substitute my photocell. Is that right?
HTML:
Black o--------------------------------+--------+
| |
| | |
R1 \ | |
185 K /<-+ |
\ v CW |
| __|__ TH1
| _\/\_ Q2008LT
+---|>| / |
| |<|--' |
C1 _|_ Diac |
.1 uF --- (part of |
S1 | TH1) |
Black o------/ ---------------------+-----------+
Also, this circuit involves a TH1 Q2008LT triac. I searched the web site, All Electronics, and they have a:
Teccor Q4015L5. Alternistor Triac - Specifically designed for applications which are required to switch highly inductive loads. 15 Amps, 400 Volts. TO220 package.