DerStrom8
Super Moderator
Good day, everyone.
I am currently working on a project that uses an LM317 adjustable voltage regulator with a 12-15 volt battery pack (not exactly sure which, yet). I know that if you want to be able to adjust the output voltage by hand, you use a pot connected to the 317. My question, though, is this: As the battery voltage drops, how much will the position of the potentiometer have to change to keep it at a specific voltage? In other words, let's say I have a 15 volt supply, and I have my potentiometer at the point where I get 9 volts from the regulator. When the supply voltage drops to, say, 12 volts, would the pot have to be in a different position to still get 9 volts from the regulator? I don't imagine this would be the case--It would make more sense if the variable resistor would stay in the same spot, but I just want to make sure.
Thanks in advance![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Der Strom
I am currently working on a project that uses an LM317 adjustable voltage regulator with a 12-15 volt battery pack (not exactly sure which, yet). I know that if you want to be able to adjust the output voltage by hand, you use a pot connected to the 317. My question, though, is this: As the battery voltage drops, how much will the position of the potentiometer have to change to keep it at a specific voltage? In other words, let's say I have a 15 volt supply, and I have my potentiometer at the point where I get 9 volts from the regulator. When the supply voltage drops to, say, 12 volts, would the pot have to be in a different position to still get 9 volts from the regulator? I don't imagine this would be the case--It would make more sense if the variable resistor would stay in the same spot, but I just want to make sure.
Thanks in advance
Der Strom