The circuit does not have a V- negative supply. Instead it has +5V, +6.8V to +18V and 0V which some people call ground.
The capacitor with dotted wires has its negative wire connected to 0V and its positive wire is connected to V-LED.
The pot has one terminal connected to 0V and the other terminal connected to +5V.
Thanks... what would i do... nobody seems to be interested in electronics in Sweden... but i just love it, i dont know so much, obviously.... i have about 20 000 leds, all kinds... but i dont know much about circuits...
Thanks for being there!, i'm so happy!
I hope you don't mind me asking questions, i can't really be of much help myself....
Is it neccessary with the capacitor?
I just can't get it to work...
I have +5v to one leg of the capacitor, the middle leg on the 5-pin (signal) on the Lm3914.
But then the other leg of the pot seems to be connected to 0V.. where do i connect the (+) side of the leds, the one's that are joined togheter.
I'm sure!, im on my way to buy a lab-powerunit now, i hate messing with batteries that needs recharging and so on...
After that i will try.
But again, is the capacitor needed?
And now i understand that i need two powersources?, didn't get that in the beginning...
One that provides 5 volt and one 9-12V
I'm sure!, im on my way to buy a lab-powerunit now, i hate messing with batteries that needs recharging and so on...
After that i will try.
But again, is the capacitor needed? If the LED's are more than 6 inches from the LM3914 then Yes.
And now i understand that i need two powersources?, didn't get that in the beginning...
One that provides 5 volt and one 9-12V You can use a resistive divider to give the 5V from the 12V.
I have always been using batteries...but from today a labunit..
Wow, much new information here
I will study it, and if you have the time and could draw a new schedule i would really appreciate it, but you dont have to, i have gotten much more help than i deserve already