Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Measuring capactitance

Status
Not open for further replies.

Mark S.

New Member
Have i got this correct.

capactitance = eA/d

e = Permittivity of dielectric.
A = Area of plate overlap in square metres
d = Distance between plates in meters.

So, a capacitor, consisting of two parallel metal
plates of overlapping area 20 cm², 10 mm apart, with a mica
dielectric, has a capacitance of:

e = 6 * 9 * (10-12)
d = 0.01 (10mm or 1cm)
A = 0.20 (20cm²)

In my book it says 20cm² is = 0.002 instead of 0.2

Am i missing something here?

How does 20cm² become 0.002 . I thought that would mean 2mm².

Thanks Mark S.
 
Suppose I have a strip of paper 1cm by 20cm, now I'll calculate the area in both cm² and m²

cm²
1*20 = 20cm²


Now:
1cm = 0.01m
20cm = 0.2m
so:
0.01*0.2 = 0.002m²

See what I mean?
 
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top