Thanks for your immediate reply. But my doubt still isn’t cleared. Sorry, I should have stated my doubt clearly.
With the conducting surface present & say a charge +Q above it, for any other test charge, the only force is due to the +Q charge. Now consider the conducting plane removed, & a charge –Q placed equally below. Now the force on any test charge will be that due to +Q as well as –Q. This is not the same as the force which was present with the conducting plane in place..
I understand that the Method of Images can’t be wrong; there is obviously some flaw in my reasoning. Kindly help me understand it..
Thanks a lot,
Regards.