More Glcd - Understanding The Code

Hi Peeps,

I recently had issues with a GLCD which with your help I managed to get working.
Trouble is I've changed from a PIC16F877 to a PIC16LF18877 and the waveform on the analyser is all messed up.

My question is:
What is going on here.. with these two lines?
(For reference GlcdControlBus is defined as PORTB, with CS1 as 0x00, & CS2 as 0x01)



I know what the end result creates, but how? I tried to break each symbol down as I try to fathom it out, but I'm struggling. It only needs to set bits<1:0> of PORTB yet seems so complicated.

regards
GB

The expression '(1<<n)' creates a bitmask value from a bit number n=0 to 7 by shifting '1' left n times.

For example, with CS2 = 1 (0x01) it evaluates as:
So,

Likewise, (1<<0) = 1 = 0x01, so

Thank you for that, and forgive my ignorance, why don't/can't I just use ....

If there are no other pins used on PORTB then you could.
It's much more common to have to read the current IO pin states, modify the pins you want, and then write them back to the PORT.

tumbleweed said:

If there are no other pins used on PORTB then you could.
It's much more common to have to read the current IO pin states, modify the pins you want, and then write them back to the PORT.

Click to expand...

Ah, so does that mean that, that bit of code (i.e. "&= ~(1<<CS1);" ) only changes a single bit at a time?

Yes.

If you look back at post #2 again you'll see that the two expressions either set bit 1 or clear bit 0 (and leave all the other bits as they are).

Cool, That's handy to know, and very useful.
Can't thank you enough for taking the time to explain.