AtomSoft Well-Known Member Jul 17, 2010 #1 Ok im getting made here but at the equations used ... Look at this equation... from ... AN954 This equation should be: SQUARE ROOT OF (2*VRMS-VZ) / 2*R1 Correct? If so then : SQUARE ROOT OF (2*120-5) / 2*1800 then SQUARE ROOT OF (235) / 3600 then 15.32970971675589 / 3600 then why is my outcome 0.0042582526990989 4.25mA and not 45.8mA ??? Attachments eq.jpg 140.9 KB · Views: 893 Last edited: Jul 17, 2010
Ok im getting made here but at the equations used ... Look at this equation... from ... AN954 This equation should be: SQUARE ROOT OF (2*VRMS-VZ) / 2*R1 Correct? If so then : SQUARE ROOT OF (2*120-5) / 2*1800 then SQUARE ROOT OF (235) / 3600 then 15.32970971675589 / 3600 then why is my outcome 0.0042582526990989 4.25mA and not 45.8mA ???
M MrAl Well-Known Member Most Helpful Member Jul 18, 2010 #3 Hello there, So you want 5v output at 45ma right, or a different current output? If you use a 1.8k resistor you'll have to make it a 12 watter or better. It's going to get rather hot too. You also need a diode or a bridge rectifier for DC output.
Hello there, So you want 5v output at 45ma right, or a different current output? If you use a 1.8k resistor you'll have to make it a 12 watter or better. It's going to get rather hot too. You also need a diode or a bridge rectifier for DC output.
AtomSoft Well-Known Member Jul 18, 2010 #4 yeah.. i got that... Take a look at this.. Im making a calculator for this kind of stuff now to help others.. Next ill add the calc for the Power and also the Capacitance version Attachments R1POWER.jpg 96.7 KB · Views: 711 Last edited: Jul 18, 2010
yeah.. i got that... Take a look at this.. Im making a calculator for this kind of stuff now to help others.. Next ill add the calc for the Power and also the Capacitance version
AtomSoft Well-Known Member Jul 18, 2010 #5 Resistive part is now done: Attachments Resistive.jpg 132 KB · Views: 690 Last edited: Jul 18, 2010