bananasiong
New Member
Hi,
I have a nokia charger that its connector is not working anymore, so I use it as the power supply of my PIC programmer and my PIC experiments. I have a 5 V low dropout voltage regulator in it (5.5 V input max). On the charger, written the output DC 5.3 V, 500 mA. So I assumed that I can use the charger for my new programmer.
I was able to use it in my house. Today, I went to my college and measured the output voltage of my charger. It was 6.1 V!!!! I connected it to my programmer, and measured the voltage of the charger (with the programmer as the load), and the voltage is 5.9 V.
Luckily I didn't burn the voltage regulator, just wonder why the output voltage of the charger is higher than as rated. I planned to use it as the power supply of my programmer, and I have mounted the voltage regulator onto the PCB
Sigh, will I harm the little voltage regulator with input voltage higher than the rated??
I have a nokia charger that its connector is not working anymore, so I use it as the power supply of my PIC programmer and my PIC experiments. I have a 5 V low dropout voltage regulator in it (5.5 V input max). On the charger, written the output DC 5.3 V, 500 mA. So I assumed that I can use the charger for my new programmer.
I was able to use it in my house. Today, I went to my college and measured the output voltage of my charger. It was 6.1 V!!!! I connected it to my programmer, and measured the voltage of the charger (with the programmer as the load), and the voltage is 5.9 V.
Luckily I didn't burn the voltage regulator, just wonder why the output voltage of the charger is higher than as rated. I planned to use it as the power supply of my programmer, and I have mounted the voltage regulator onto the PCB
Sigh, will I harm the little voltage regulator with input voltage higher than the rated??