windozeuser Member Oct 31, 2010 #1 I need to select components in multisim that will give an impedance of (3 + j4) Now to calculate inductive reactance the forumula is XL = 2(pi)FL I need to calculate the inductance value for the needed impedance so... j4/(2(pi)60) = inductance needed? I am connecting this to a 60Hz AC source, I wouldn't use (3 + j4) , just j4 right in the calculation? the 3 is a real part which is a 3 ohm resistor?
I need to select components in multisim that will give an impedance of (3 + j4) Now to calculate inductive reactance the forumula is XL = 2(pi)FL I need to calculate the inductance value for the needed impedance so... j4/(2(pi)60) = inductance needed? I am connecting this to a 60Hz AC source, I wouldn't use (3 + j4) , just j4 right in the calculation? the 3 is a real part which is a 3 ohm resistor?
RCinFLA Well-Known Member Oct 31, 2010 #2 You can put a 10.6 mH coil in series with 3 ohm resistor. Or put 16.6 mH coil in parallel with 8.33 ohm resistor. Both equal 3 + j4 at 60 Hz. Last edited: Oct 31, 2010
You can put a 10.6 mH coil in series with 3 ohm resistor. Or put 16.6 mH coil in parallel with 8.33 ohm resistor. Both equal 3 + j4 at 60 Hz.
RCinFLA Well-Known Member Oct 31, 2010 #4 If you do this for real, be aware of the resistance equivalence within the inductor.