Hi,
Take out the two fat diodes (first photo, just above main xfmr), you will be isolating the main output to the amplifier circuit. One of these diodes could be shorted...just as a tip...
Also there are three smaller diodes, providing auxilliary supply to amplifier circuit.
The small daughter board is actually the controller for the main mosfets.
There are two "reddish" capacitors between the daughterboard and the big PS capacitor. Those two are part of the half bridge topology of the input converter. The other half being the two mosfets. As I said in a previous post, its a self oscillating half bridge dc-dc converter. The small daughterboard should have also a DIAC on it, which provides for a turn-on pulse and afterwards it is kept off by the oscillations of the converter, of course if it starts. This kind of converter also needs a minimum load, to continue operating. This kind of PS were used in early days as "lightweight transformers", to power the halogen lamps.
At the moment I don't have a generic schematic handy but I believe you can find one on the net, just to get an idea, how the circuit operates.
It is very possible, that you have a short in the amplifier circuitry, preventing the main PS to start and remain locked, blowing the fuse. The advice to use a 100W bulb instead of a fuse is fully correct and enables you to actually power the circuit without blowing things.
What was the rating of the original fuse?
Tonight I traced down the schematic of the other daughter board, the one which works at the secondary side, doing the main job of tracking the output power needed by the amps, by varying the voltage supplied to the output transistors.
Probably if I get too pissed off by this lousy circuit I'll do the same for the input doughterboard, even maybe for the entire circuit... Then I will post it. I hate when people try to hide "hot water" inventions...