Hello there,
My understanding of this question up to this point is that the original drawings were wrong in that the non inverting and inverting terminals were drawn as swapped. To correct this we swap the two and then we have simply two regular inverting amplifiers with two resistors. So we are really starting with just two plain inverting amplifiers.
My guess is that you are MEASURING the two inputs and then concluding that since they are the same for both circuits the outputs should be the same. But that's not how op amps work. The inputs could be very NEARLY the same, yet have different outputs, and this is very normal and even necessary. So the two LOOK like they are the same, but they are in fact a tiny bit different, and that difference gets amplified and appears at the output, and the feedback resistor and other resistor form a voltage divider that provides a feedback voltage that is ALMOST the same as the non inverting input terminal voltage but NOT exactly the same. This slightly different voltage is probably the cause of the confusion.
The resistor ratio A1 for the first amplifier can be calculated from:
5/(A1+1)=0.6
and the resistor ratio A2 for the second amplifier can be calculated from:
7.35/(A2+1)=0.9
Solving these for A1 and A2, we see that:
A1=22/3, and
A2=43/6
Note that if A2 was 44/6 (close to 43/6) these two would be exactly the same, and indicative of the resistor values being say 22k and 3k for example, or any other two that are the same ratio and are not too low in value.
So lets figure out the mean and see what happens...
((22/3)+(43/6))/2=29/4
so between the two we have an average ratio of 29/4 in both amplifiers, and this is not much different from the more accurate gains for the two A1 and A2. So we'll call this A3: A3=29/4
Now we know that the input of the first amp is 0.6v, and the second amp the input is 0.9v, so we'll calculate the output for both amps:
Vout1=0.6*(A3+1)=0.6*(29/4+1)=4.95 volts
and:
Vout2=0.9*(A3+1)=0.9*(29/4+1)=7.425 volts
Already we can see that we have something that is quite close to the real life measurements, so the circuits appear to be working close to the theoretical.
Add resistor tolerances to this calculation and a little input offset, and we might see exactly what was actually measured in the first post.
Taking more accurate measurements would reveal more about the circuits. It could be that one circuit has worse resistor values. To find out, swap all the resistors from one amp to the other and vice versa and see how that affects the real world measurements.