superflux,
You did not understand my last post about driving a LED. You do not have one output =1 and the other =0!
The pins have three states. 1, 0, Z (z=input)
pin1, pin2, current
0, 0, 10mA
Z, 0, 8mA
0, Z, 2mA
Z, Z, 0mA
superflux,
You did not understand my last post about driving a LED. You do not have one output =1 and the other =0!
The pins have three states. 1, 0, Z (z=input)
pin1, pin2, current
0, 0, 10mA
Z, 0, 8mA
0, Z, 2mA
Z, Z, 0mA
On the contrary, I did understand and I thought it was a good solution.
I was simply asking if the when 2 or more PORTs are set to OUTPUT and are connected and one of them is "1" and the other is "0", does that "0" represent 'ground' and if so, can I assume that it will ground out the voltage sent from the other connected PORT that is set to "1" (high)?
I guess what I'm asking is when an OUTPUT port is set to "0" is that GROUND or just 0 volts?