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Hi i managed to get the following solution, but I am not sure whether it is right.
Vc(t) = VoRc/R1 + Ke^(-t/RcCc)
where K is a constant. It doesn't seem correct to me, since if you choose the resistors in a certain way then you can get Vc(t) > V0.
B3=C1*C2*C3*R1*R2*R3*Rs
B2=C1*C2*R1*R2*R3+C1*C2*R1*R2*Rs+C1*C3*R1*R2*R3+C1*C3*R1*R3*Rs+C2*C3*R1*R2*R3+C2*C3*R2*R3*Rs
B1=C1*R1*R2+C1*R1*R3+C1*R1*Rs+C2*R1*R2+C2*R2*R3+C2*R2*Rs+C3*R1*R3+C3*R2*R3+C3*R3*Rs
B0=R1+R2+R3+Rs
A2=V*R2*C1*C3*R1*R3
A1=V*R2*(C1*R1+C3*R3)
A0=V*R2
Hi i have been asked to analyse the attached circuit. I need to find the voltage across the resistor Rc as a function of V and time. I dont know what method to use, any help would be much appreciated.
My Jr. Collage teacher was right to advise me to drop engineering in 1970
The problem you have given is written as a steady state problem. There is no information about how things will change in time. In other words, we need to know if the voltage is off and then turned on at time=0. Also, one would need to know the initial values of the capacitor voltages.
Basically, all voltages and currents are constant (in time) based on the way the problem is presented right now. Was more information given?