Okay so i decided to created a distortion effect that limits the signal.
If the signal looks like a sine, the upper and lower peaks should be
cut off.
I thought i'd do it with this:
![Diode limiter..JPG Diode limiter..JPG](https://www.electro-tech-online.com/data/attachments/34/34357-a96520b6e7cc20e5f888e5b4e05ec9e2.jpg)
The 10V AC signal represents the input of the guitar. The guitar signal varies from
0-4V according to how hard you strum the strings, but this is just a simulation.
This part still works: if i adjust the two DC sources, i can vary the cutoff value of
the guitar signal. In the picture the sources are 3V and -3V so the signal is cutoff
at 3,7V and -3,7V(including the diode voltage drop).
What i want is to adjust the voltages at the same time using just one potentiometer.
Thats why i builded this adjustable symmetric supply:
![symmetric supply&#.JPG symmetric supply&#.JPG](https://www.electro-tech-online.com/data/attachments/34/34358-0441d361a8a324c92fa0f87644fb686c.jpg)
The supply consists of a 9V battery and a voltage divider.
By varying the potentiometer i can adjust the V+ and V-(referenced to ground) to
0 to 4,5 and 0 to -4,5. Which is perfect for my guitar signal.
I thought i could now just hook it up to the other circuit(V+ below the first diode and V-
below the second). It doesn't work??!!!
Maybe it's really stupid what i'm trying right now, i am pretty new at circuit design
but i have studied a lot of theory.
Somebody, please help me!!!
If the signal looks like a sine, the upper and lower peaks should be
cut off.
I thought i'd do it with this:
![Diode limiter..JPG Diode limiter..JPG](https://www.electro-tech-online.com/data/attachments/34/34357-a96520b6e7cc20e5f888e5b4e05ec9e2.jpg)
The 10V AC signal represents the input of the guitar. The guitar signal varies from
0-4V according to how hard you strum the strings, but this is just a simulation.
This part still works: if i adjust the two DC sources, i can vary the cutoff value of
the guitar signal. In the picture the sources are 3V and -3V so the signal is cutoff
at 3,7V and -3,7V(including the diode voltage drop).
What i want is to adjust the voltages at the same time using just one potentiometer.
Thats why i builded this adjustable symmetric supply:
![symmetric supply&#.JPG symmetric supply&#.JPG](https://www.electro-tech-online.com/data/attachments/34/34358-0441d361a8a324c92fa0f87644fb686c.jpg)
The supply consists of a 9V battery and a voltage divider.
By varying the potentiometer i can adjust the V+ and V-(referenced to ground) to
0 to 4,5 and 0 to -4,5. Which is perfect for my guitar signal.
I thought i could now just hook it up to the other circuit(V+ below the first diode and V-
below the second). It doesn't work??!!!
Maybe it's really stupid what i'm trying right now, i am pretty new at circuit design
but i have studied a lot of theory.
Somebody, please help me!!!