justinpugh
New Member
Hi All
I have a NEWTRENT IMP500 battery. The battery has output of 5V,600mA. I use it to run a an LED conected via a bucktoot 7027. The buck toot ensures a steady output of 350mah. The problem I have is the battery has a sensor on it that switches of if the led is switched of. The LED has a switch on it and when switched of there is no draw from the battery. If left of for 30secs the battery itself switches off and when the led is next required you have to switch the LED on and the battery. It sounds simple but is a pain as the battery switch needs to be depressed for 2 secs to come.
To overcome this problem I have fitted a resistor and LED to the main led unit switch. This LED ensures that there is a constant draw from the battery if if the main LED is off.
Can anyone help me calculate the resistor and LED I need to ensure a) the resistor doesnt heat up and b) the LED doesnt burn out overtime.
I believe that the minimum draw from the battery is .03mA before the battery switches of..
Please can you show the workings so that I know how to do it. Thanks very much fro your help...
Justin
I have a NEWTRENT IMP500 battery. The battery has output of 5V,600mA. I use it to run a an LED conected via a bucktoot 7027. The buck toot ensures a steady output of 350mah. The problem I have is the battery has a sensor on it that switches of if the led is switched of. The LED has a switch on it and when switched of there is no draw from the battery. If left of for 30secs the battery itself switches off and when the led is next required you have to switch the LED on and the battery. It sounds simple but is a pain as the battery switch needs to be depressed for 2 secs to come.
To overcome this problem I have fitted a resistor and LED to the main led unit switch. This LED ensures that there is a constant draw from the battery if if the main LED is off.
Can anyone help me calculate the resistor and LED I need to ensure a) the resistor doesnt heat up and b) the LED doesnt burn out overtime.
I believe that the minimum draw from the battery is .03mA before the battery switches of..
Please can you show the workings so that I know how to do it. Thanks very much fro your help...
Justin