Problem in code

[Jyothi@Pic]

Hi,

I am using PIC18f4620 and c18 compiler below is the code when i execute this code the controller does not goto interrupt routine break point is at isr.

If their is any mistake please tell me what corrections is to be made

#include <p18f4620.h>
 #include <timers.h>

 #define NUMBER_OF_LEDS 8

 void timer_isr (void);

 static unsigned char s_count = 0;

 #pragma code low_vector=0x18
 void low_interrupt (void)
 {
	 _asm GOTO timer_isr _endasm
 }

 #pragma code

 #pragma interruptlow timer_isr
 void timer_isr (void)
 {
 	static unsigned char led_display = 0;

 	INTCONbits.TMR0IF = 0;

 	s_count = s_count % (NUMBER_OF_LEDS + 1);

	led_display = (1 << s_count++) - 1;

 	PORTB = led_display;
 }

 void main (void)
 {
 	TRISB = 0;
 	PORTB = 0;

 	OpenTimer0 (TIMER_INT_ON & T0_SOURCE_INT & T0_16BIT);
 	INTCONbits.GIE = 1;

	while (1)
 	{
 	}
}

 

[Jyothi@Pic]

Please some body reply for the above mail

 

[Pommie]

When you pause the code, what value is in INTCON?

Mike.

 

[Jyothi@Pic]

INTCON=0X07 is the value

 

[Pommie]

Timer 0 interrupt enable bit is bit 5. This is the problem when you use library routines rather than write the code yourself.

Mike.

 

[Jyothi@Pic]

hai

INCON register has 0xA0 value.

 

[Jyothi@Pic]

INTCON register has 0xA0 value on overflow INTCONbits.TMR0IF=0 is not becoming high so control is not going to isr I am not able to find what is the problem could anybody Please help me.

 

[Pommie]

You have now made two statements,

INTCON=0X07 is the value

and,

INTCON register has 0xA0 value. (T added)

You either changed something or you are mistaken.

How do you expect help when we don't know the problem?

Mike.