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is it 27.8V?
Ir=(12-0.7)/10k = 1.13mA ........ (1)
Ir=Ic+IB1+IB2 ;
Ir=Ic+(2*Ic/Bo)------------->(beta)
Ir=Ic(1+2/Bo)
from (1),
1.13=Ic(1+2/100)
=> Ic=1.107mA
Ic of trans1 = Ic of Trans2 =Ic' =(50-V2)/20k = 1.107
=> V2=27.86V
that ok?