im looking at the datasheet.. **broken link removed**
and noticed it states the low battery out put and also the data outputs low low wen operated. Does that mean that I would connect a led to the vcc (5v) and the gnd to the pin on the ic, same with the outputs, would i connect a relay to the vcc and its ground to the relevent pin on the ic?
Sorry, I was thinking of a different chip set, it looks like the outputs are 'active low' so when an output is set, the pin goes low - so they sink current rather than source it.
So in basic terms for a noob such as myself, I would connect the v-in side of a relay to vcc, the gnd to the pin on the decoder, and wen active the IC would connect the gnd side to gnd?
You need to feed the relay with a transistor, the IC won't feed a relay directly. I would suggest getting the IC's and measuring what the acrual outputs do.
Ok i will try and hook it up over the weekend thanks alot.
As for the LED for the low battery o/p, it says states the pin o/p goes low when the condition is detected, so I guess the same applies, connect the gnd of the led to the pin pn the ic?
Ok i will try and hook it up over the weekend thanks alot.
As for the LED for the low battery o/p, it says states the pin o/p goes low when the condition is detected, so I guess the same applies, connect the gnd of the led to the pin pn the ic?
I had a read, it seems pretty vague - at one point it says 25mA, and at another only 1mA - yet it shows an LED connected with no series resistor?. Assuming it is a PIC (which as far as I'm aware RF Solutions use) then it's 20-25mA per pin.
The max allowed output current from a PIC is 25mA but they can supply 60mA for a moment then burn out if the supply is 5.0V.
When the supply voltage drops then the max output current from a PIC also drops.
Of course an LED needs a current-limiting resistor or circuit. It is not a resistor like an incandescent light bulb heater, it is a diode with a certain spec'd forward voltage. An LED is fed with current, not voltage. So a current-limiting resistor or circuit must feed an LED.