skmdmasud
Member
Hi.
This is from the datasheet
X1 and X2 are the two pins where we connect a crystal.
1. If i connect 1 leg of crystal in X1 only & leave the other leg disconnected then will my RTC start to give accurate time.
2. X2 becomes floated so what happens if i ground it. As i remember we dont want to keep pins in floating state.
i am asking this because I am receiving some noise in my RTC most probable from the crystal side.
Regards...
This is from the datasheet
Code:
Connections for Standard 32.768kHz Quartz Crystal. The internal oscillator circuitry is
designed for operation with a crystal having a specified load capacitance (CL) of 12.5pF.
X1 is the input to the oscillator and can optionally be connected to an external 32.768kHz oscillator.
The output of the internal oscillator, X2, is floated if an external oscillator is connected to X1.
1. If i connect 1 leg of crystal in X1 only & leave the other leg disconnected then will my RTC start to give accurate time.
2. X2 becomes floated so what happens if i ground it. As i remember we dont want to keep pins in floating state.
i am asking this because I am receiving some noise in my RTC most probable from the crystal side.
Regards...