250 uA is typical. however, the minimum is 50 uA and max is 400 uA. typical wide range for mos. So, a good design needs to take the range into account.
This depends on what voltage you are running your pic at and whether the pin has a TTL or CMOS input level. If TTL, it should work but most PICs have CMOS levels so read on. You can tell by finding "minimum Voltage input high" on the dtatsheet. If it's .8Vcc then it's a CMOS input. Running the PIC at 5V gives you a minimum high input level of 4V.
I don't think your diagram works but why don't you just try it, it's not going to smoke the pic or anything. I predict the voltage at the pin will be something like 2.7V with the switch open, 20K WPUs and pin in input mode. Too low. You've got the led/resistor pulling down a lot harder than the wpus are pulling up even when you are starting with 2V drop of the LED.
You will want to get the "floor" above 4V. You could do this in several ways. Add a couple of silicon diodes in series with the led (I'd try 3, 2 isn't enough). Or add a second led. 2 leds would put the switch open voltage at about 4.7V or so depending on the resistor drop. The switch should short the pin to ground (get rid of R7).
Phil