Electronman
New Member
Hi,
Today a friend asked me to explain the relationship between the voltage and the current of a capacitor when connected to an AC (sinusoidal) source.
After doing so, and showing him the 90 degrees phase difference between the voltage and the current, I came across a problem in my mind.
At the peak point of the current (which means the current is feed backed to the source) the voltage is zero. This means the current will pass through the power source when the voltage of the source is at 0V!
The question:
Why the current flows at 0V in this condition?
I was thinking of a short circuit where the voltage tends to be zero and in this situation we replace the voltage source with a wire. But I am not sure if this the key to solve my problem? I have heard the short and open circuits for DC circuits, but I think they can be used here for an AC source!
Now that I am thinking of a short circuit, I am wondering why a voltage source is assumed to be a short circuit when the voltage is zero?
Thanks in advance
Today a friend asked me to explain the relationship between the voltage and the current of a capacitor when connected to an AC (sinusoidal) source.
After doing so, and showing him the 90 degrees phase difference between the voltage and the current, I came across a problem in my mind.
At the peak point of the current (which means the current is feed backed to the source) the voltage is zero. This means the current will pass through the power source when the voltage of the source is at 0V!
The question:
Why the current flows at 0V in this condition?
I was thinking of a short circuit where the voltage tends to be zero and in this situation we replace the voltage source with a wire. But I am not sure if this the key to solve my problem? I have heard the short and open circuits for DC circuits, but I think they can be used here for an AC source!
Now that I am thinking of a short circuit, I am wondering why a voltage source is assumed to be a short circuit when the voltage is zero?
Thanks in advance