Could you explain a little bit how this bootstrap works?
The followng circuit shows a bootstrap using the load and the output capacitor, which is clear enough for me to understand.
The bootstrapping consists of two resistors, with a capacitor feeding the middle of them - in this case the top resistor is replaced by the speaker, and the capacitor replaced by the speaker coupling capacitor. And contrary to Audioguru's concerns the DC current through the speaker is absolutely tiny, and of no concern whatsoever - it's a perfectly acceptable circuit configuration, and saves a capacitor and a resistor (however, I'm with AG in that I wouldn't design an amplifier in that way).
The way bootstrapping works is quite simple - in the case of the design above the top output transistor is limited to how far positive it can go, due to the resistor feeding the base.
For an example, assume the resistor is 1000 ohms, and the supply voltage is 40V, with no signal there's roughly 20V across the resistor, giving 20mA drive capability to the output transistor.
If the output swings positive by 10V, this means only 10mA drive, and for 15V (leaving 5V across the resistor), only 5mA drive - even worse, as the output goes higher it draws more current, while the drive capability is falling. This causes considerable distortion, and greatly reduces possible output power.
By connecting a capacitor from the output to the top of the resistor, as the output swings positive the top of the resistor swings positive as well, maintaining the voltage across the resistor, and thus maintaining the current drive capability.
A more modern way is to replace the bootstrapping with a constant current source, which gives a similar result.